Matematika Sekolah Menengah Pertama bantu Exponensial kelas 10
[tex] \sqrt[5]{ \frac{1}{243} } + \sqrt[3]{ \sqrt{729} } + \sqrt{ \sqrt[3]{ \frac{1}{64} } } = [/tex]
babtu​

bantu Exponensial kelas 10
[tex] \sqrt[5]{ \frac{1}{243} } + \sqrt[3]{ \sqrt{729} } + \sqrt{ \sqrt[3]{ \frac{1}{64} } } = [/tex]
babtu​

23 = 3 5

6 6

Penjelasan

Cara ada di gambar

Penjelasan dengan langkah-langkah:

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[tex]\displaystyle \bf \sqrt[5]{\frac{1}{243}} + \sqrt[3]{\sqrt{729}} + \sqrt{\sqrt[3]{\frac{1}{64}}}[/tex]

[tex]=\displaystyle \bf \sqrt[5]{\frac{1}{3^5}} + \sqrt[3]{\sqrt{27^2}} + \sqrt{\sqrt[3]{\frac{1}{4^3}}}[/tex]

[tex]= \displaystyle \bf \frac{\sqrt[5]{1}}{\sqrt[5]{3}} + \sqrt[3]{27} + \sqrt{\frac{1}{4}}[/tex]

[tex]= \displaystyle \bf \frac{1}{3} + \sqrt[3]{3^3} + \frac{\sqrt{1}}{\sqrt{4}}[/tex]

[tex]= \displaystyle \bf \frac{1}{3} + 3 + \frac{1}{2}[/tex]

[tex]= \displaystyle \frac{1}{3} + \frac{3}{1} + \frac{1}{2}[/tex]

[tex]= \displaystyle \frac{1 \times 2}{3 \times 2} + \frac{3 \times 6}{1 \times 6} + \frac{1 \times 3}{2 \times 3}[/tex]

[tex]= \displaystyle \frac{2}{6} + \frac{18}{6} + \frac{3}{6}[/tex]

[tex]= \displaystyle \bf \frac{2 + 18 + 3}{6}[/tex]

[tex]= \displaystyle \bf \frac{23}{6}[/tex]

[tex]= \displaystyle \bf 3\frac{5}{6}[/tex]

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